Square root

[Michael Lee]

Am I the only person who didn't know this!?!? Oh well it's not the first time.

Thanks again to everyone who replied.


Michael Lee
MCL Systems Inc.


Ray Bailey wrote:

> I didn't know this until today either.
>
> After a bit of experimenting I've found that Matt Ohmes' suggestion would be
> better if you ever wanted to find the cubed route etc. It doesn't look very
> different 1/2 = 0.5 but when it comes to recursive decimal places that's a
> different matter.
>
> x = 27^(1/3) = 3
> x = 27^0.3333 = 2.99967
>
> +---------------------------------------------------------------+
> | Ray Bailey                    |  Yesterday is history,        |
> | Specialist Business Solutions |  Tomorrow is a mystery.       |
> | Tel   : 01788 822133          |  Today is a gift,             |
> | Fax   : 01788 823601          |  That's why they call it      |
> | Email : rayb@specialist.co.uk |                 the present.  |
> | URL   : www.specialist.co.uk  |  Cathal Smyth 1999            |
> +---------------------------------------------------------------+
>
> -----Original Message-----
> From: owner-powerh-l@sphere.swau.edu
> [mailto:owner-powerh-l@sphere.swau.edu]On Behalf Of Michael Lee
> Sent: 18 February 2000 18:04
> To: Powerhouse User List
> Subject: Square root
>
> I was wondering if anyone knows of a QDESIGN technique to get the square
> root of a number. As far as I can see there is no existing Powerhouse
> function that does this. Please feel free to correct me if I'm wrong.
>
> Thanks in advance for any help.
>
> Michael Lee
> MCL Systems Inc.
>
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